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Distancia entre os pontos- plano carteziano
Durante o seu treinamento ,um ciclista (vivelindio era o nome dele ) determinou o seu circuito em coordenadas cartesianas,definindo os pontos a(1,2),b(10,10)e c(14,4).Calculando as distancia entre esses pontos e possível descobrir quanto vivelindio percorre em cada treino.O circuito mede aproximadamente :
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Answer #
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Answer #1
Projetando-se os pontos no plano cartesiano, temos:
d (ab) = 9
d (bc) = 6
d (ca) = 13
distância do circuito = 28
Obs.: não fornecido unidade de medida