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Questão de Velocidade de um bloco em m/s
Um feixe de balas com massa de 3g cada é disparado com velocidade de 1000 m/s contra um bloco de madeira de 10 kg, inicialmente em repouso numa mesa horizontal de atrito desprezível.Qual será a velocidade do bloco, em m/s, após absorver 20 balas?
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Answer #1
Mbala = 3 g = 3*10e-3 kg
Mbloco = 10 kg
vbala = 10e3 m/s
1a. bala:
Mbala*vbala = (Mbloco+Mbala)*V
Mbloco+Mbala ~ Mbloco
V1=(Mbala/Mbloco)vbala
2a.bala:
Mbala*vbala + (Mbloco*V1) = Mbloco*V2
Mbala*vbala + Mbala*vbala = Mbloco*V2
2Mbala*vbala = Mbloco*V2
n-sima bala:
n*Mbala*vbala = Mbloco*Vn
20a. bala:
20*Mbala*vbala = Mbloco*V20
20*0,003*1000=10*V20
V20 = 6m/s